思路：先对 nums2 用单调栈求每个元素的下一个更大值，存入 Map 缓存；再遍历 nums1 直接查 Map 得结果。时间复杂度 O(len1 + len2)。
Раскрыты подробности о договорных матчах в российском футболе18:01
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50MP main, 12MP ultrawide, 10MP 3x telephoto
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